By R. J. Mitchell (auth.)
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10(. ~,' ,,/ ~}. ~. L. ~ ~ r-... r-.... I" 1""r--.. 4 Missed pixels problem The basic idea of the FillTriangle routine is as follows: for all y coordinates between the top and the bottom of the triangle, to calculate the x position of the two lines of the triangle which exist at that y coordinate, and to draw a horizontal line between them. 5, the algorithm starts at position A, and then progresses down the lines AB and AC, calculating the x coordinates on these lines for each y value, and drawing horizontal lines between them, until point 36 Modula-2 Applied B is reached.
If the queen is drawn on a black square, a white queen should be drawn, otherwise a black queen should be drawn. Now solve the rest of the problem. 5) Modify the program so that it finds all 92 solutions to the puzzle. 6) Most of these solutions are rotations or mirror images of each other. Modify the program to find the 12 distinct solutions only. 7) Write a program to find one solution to the Knights Tour problem starting from one comer of the board. Develop the program on a 5*5 chess board, and then gradually increase the size of the board.
Ds DIV da; incr1 := 2 * (ds MOD da); decision := incr1 - da; incr2 := decision - da; A := a1; (* A set to first of always variable 5 := sl; UpA := a1 <= a2; (* indicate if A should be changed each time UpS := sl <= s2 END END SetLineRec; - PROCEDURE NextLine (VAR L : LineRec); (* this calculates next 'X,Y' position of line defined by L *) BEGIN WITH L DO IF decision < 0 THEN INC (decision, incr1); IF UpS THEN INC (5, alwaysIncr) ELSE DEC (5, alwaysIncr) END ELSE INC (decision, incr2); IF UpS THEN INC (5, l+alwaysIncr) ELSE DEC (5, l+alwaysIncr) END END; IF UpA THEN INC (A) ELSE DEC (A) END END END NextLine; *) *) *) *) Introductory Program 29 PROCEDURE Line (xl, yl, x2, y2, colour INTEGER); (* draw line *) PROCEDURE ActualLine (al, sl, a2, s2 : INTEGER; swap: BOOLEAN); (* This actually draws the line, processing always and sometimes variables al, a2 and sl, s2.